Match each subspace with a basis for that subspace. (You may assume that each set is really a basis for at least one of the subspaces.)
Each putative basis is a subset of exactly one of the three subspaces. So for each subspace, two of the three sets can be ruled out by simply testing that the vectors of the basis are members of the subspace, via the membership criteria.
\(\left\{\langle x,y,z\rangle\mid - y + z = 0\right\}\)
Sort the following functions into their correct categories. [Ed. As of 2024-10-07 the following problem is not expected to render and function properly. It is here to aid development work. Nothing to see here.]
