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PreTeXt Sample Book Abstract Algebra (SAMPLE ONLY)

Worksheet 3.26 A β€œGroup Work” Worksheet

View Source for worksheet
<worksheet groupwork="yes" groupsize="2" xml:id="worksheet-groupwork">

  <title>A <q>Group Work</q> Worksheet</title>

  <p>
    This is a <tag>worksheet</tag> which has a <attr>groupwork</attr> attribute set to <c>yes</c>, along with a <attr>label</attr> attribute to assist with the Runestone database.
    Note, you can also set a <attr>groupsize</attr> attribute.
    When hosted on Runestone, the exercises within will be available for a group of students to submit together.
  </p>

  <exercise label="groupwork-multiple-choice">

    <title>Multiple-Choice, Group Work</title>

    <idx>stop signs</idx>

    <idx>group work</idx>

    <statement>

      <p>
        What color is a stop sign?
      </p>

    </statement>

    <choices>

      <choice>

        <statement>

          <p>
            Green
          </p>

        </statement>

        <feedback>

          <p>
            Green means <q>go!</q>.
          </p>

        </feedback>

      </choice>

      <choice correct="yes">

        <statement>

          <p>
            Red
          </p>

        </statement>

        <feedback>

          <p>
            Red is universally used for prohibited activities or serious warnings.
          </p>

        </feedback>

      </choice>

      <choice>

        <statement>

          <p>
            White
          </p>

        </statement>

        <feedback>

          <p>
            White might be hard to see.
          </p>

        </feedback>

      </choice>

    </choices>

    <hint>

      <p>
        What did you see last time you went driving?
      </p>

    </hint>

    <hint>

      <p>
        Maybe go out for a drive?
      </p>

    </hint>

  </exercise>

  <p>
    Worksheets allow for material interleaved with the <tag>exercise</tag> throughout.
  </p>

  <exercise label="groupwork-number-theory" adaptive="yes" language="natural">

    <title>Parsons Problem, Group Work</title>

    <idx>even numbers</idx>

    <idx>groupwork</idx>

    <statement>

      <p>
        Create a proof of the theorem: If <m>n</m> is an even number, then <m>n\equiv 0\mod 2</m>.
      </p>

    </statement>

    <blocks> <block order="2">

    <p>
      Suppose <m>n</m> is even.
    </p>

    </block> <block order="3">

    <choice>

      <p>
        Then <m>n</m> is a prime number.
      </p>

    </choice>

    <choice correct="yes">

      <p>
        Then there exists an <m>m</m> so that <m>n = 2m</m>.
      </p>

    </choice>

    <choice>

      <p>
        Then there exists an <m>m</m> so that <m>n = 2m + 1</m>.
      </p>

    </choice>

    </block> <block order="1" correct="no">

    <p>
      Click the heels of your ruby slippers together three times.
    </p>

    </block> <block order="5">

    <p>
      So <m>n = 2m + 0</m>.
    </p>

    <p>
      This is a superfluous second paragraph in this block.
    </p>

    </block> <block order="4">

    <p>
      Thus <m>n\equiv 0\mod 2</m>.
    </p>

    </block> <block order="6" correct="no">

    <p>
      And a little bit of irrelevant multi-line math
      <md>

        <mrow>c^2&amp;a^2+b^2</mrow>

        <mrow>&amp;x^2+y^2</mrow>

      </md>.

    </p>

    </block> </blocks>

    <hint>

      <p>
        Dorothy will not be much help with this proof.
      </p>

    </hint>

  </exercise>

</worksheet>
This is a <worksheet> which has a @groupwork attribute set to yes, along with a @label attribute to assist with the Runestone database. Note, you can also set a @groupsize attribute. When hosted on Runestone, the exercises within will be available for a group of students to submit together.

1. Multiple-Choice, Group Work.

View Source for exercise
<exercise label="groupwork-multiple-choice">

  <title>Multiple-Choice, Group Work</title>

  <idx>stop signs</idx>

  <idx>group work</idx>

  <statement>

    <p>
      What color is a stop sign?
    </p>

  </statement>

  <choices>

    <choice>

      <statement>

        <p>
          Green
        </p>

      </statement>

      <feedback>

        <p>
          Green means <q>go!</q>.
        </p>

      </feedback>

    </choice>

    <choice correct="yes">

      <statement>

        <p>
          Red
        </p>

      </statement>

      <feedback>

        <p>
          Red is universally used for prohibited activities or serious warnings.
        </p>

      </feedback>

    </choice>

    <choice>

      <statement>

        <p>
          White
        </p>

      </statement>

      <feedback>

        <p>
          White might be hard to see.
        </p>

      </feedback>

    </choice>

  </choices>

  <hint>

    <p>
      What did you see last time you went driving?
    </p>

  </hint>

  <hint>

    <p>
      Maybe go out for a drive?
    </p>

  </hint>

</exercise>
What color is a stop sign?
  • Green
  • Green means β€œgo!”.
  • Red
  • Red is universally used for prohibited activities or serious warnings.
  • White
  • White might be hard to see.
Hint 1.
View Source for hint
<hint>

  <p>
    What did you see last time you went driving?
  </p>

</hint>
What did you see last time you went driving?
Hint 2.
View Source for hint
<hint>

  <p>
    Maybe go out for a drive?
  </p>

</hint>
Maybe go out for a drive?
Worksheets allow for material interleaved with the <exercise> throughout.

2. Parsons Problem, Group Work.

View Source for exercise
<exercise label="groupwork-number-theory" adaptive="yes" language="natural">

  <title>Parsons Problem, Group Work</title>

  <idx>even numbers</idx>

  <idx>groupwork</idx>

  <statement>

    <p>
      Create a proof of the theorem: If <m>n</m> is an even number, then <m>n\equiv 0\mod 2</m>.
    </p>

  </statement>

  <blocks> <block order="2">

  <p>
    Suppose <m>n</m> is even.
  </p>

  </block> <block order="3">

  <choice>

    <p>
      Then <m>n</m> is a prime number.
    </p>

  </choice>

  <choice correct="yes">

    <p>
      Then there exists an <m>m</m> so that <m>n = 2m</m>.
    </p>

  </choice>

  <choice>

    <p>
      Then there exists an <m>m</m> so that <m>n = 2m + 1</m>.
    </p>

  </choice>

  </block> <block order="1" correct="no">

  <p>
    Click the heels of your ruby slippers together three times.
  </p>

  </block> <block order="5">

  <p>
    So <m>n = 2m + 0</m>.
  </p>

  <p>
    This is a superfluous second paragraph in this block.
  </p>

  </block> <block order="4">

  <p>
    Thus <m>n\equiv 0\mod 2</m>.
  </p>

  </block> <block order="6" correct="no">

  <p>
    And a little bit of irrelevant multi-line math
    <md>

      <mrow>c^2&amp;a^2+b^2</mrow>

      <mrow>&amp;x^2+y^2</mrow>

    </md>.

  </p>

  </block> </blocks>

  <hint>

    <p>
      Dorothy will not be much help with this proof.
    </p>

  </hint>

</exercise>
Create a proof of the theorem: If \(n\) is an even number, then \(n\equiv 0\mod 2\text{.}\)
Hint.
View Source for hint
<hint>

  <p>
    Dorothy will not be much help with this proof.
  </p>

</hint>
Dorothy will not be much help with this proof.